Answer:
True
Explanation:
Ethers react with HI to form the corresponding alcohols and alkyl iodides.
Similarly, ethyl ether react with excess of HI to form ethanol and ethyl iodide. But in the excess of HI as mentioned in the question, ethanol too undergoes [tex]S^{N}2[/tex] reaction with HI to form ethyl iodide.
Hence, ethyl iodide is the only product when ethyl ether reacts with excess of HI for several hours.