Question

The label on the car's antifreeze container claims to protect the car between −30°C and 130°C. To covert Celsius temperature to Fahrenheit temperature, the formula is C equals five ninths times the quantity F minus thirty two.. Write a compound inequality to determine the Fahrenheit temperature range at which the antifreeze protects the car. Negative thirty is greater than five ninths times the quantity F minus thirty two is greater than one hundred thirty. Negative thirty is less than five ninths times the quantity F minus thirty two is less than one hundred thirty. Negative thirty is less than five ninths times the quantity F minus thirty two. Five ninths times the quantity F minus thirty two is less than one hundred thirty.

Answer 1

Answer:

F=C(9/5)+32

then sub both Celsius values in the formula

F=-30 (9/5)+32

=-22

F=130 (9/5)+32

=266

to the antifreeze protects the car between -22°F and 266°

Answer 2

Answer:

$-22 ^\circ F \leq Temperature \leq 266 ^\circ F$        

Step-by-step explanation:

We are given the following information in the question:

The car's antifreeze container claims to protect the car between −30°C and 130°C.

We have to convert this temperature into Fahrenheit.

The conversion is as follows:

$T_{(^\circ F)} = T_{(^\circ C)}\times \displaystyle\frac{9}{5} + 32,\\T_{(^\circ F)}\text{ is the temperature in Fahrenheit}\\T_{(^\circ C)}\text{ is the temperature in Celsius}$

Thus, the conversion takes place as follows:

$T_{(^\circ F)} = -30\times \displaystyle\frac{9}{5} + 32 = -22 ^\circ F\\\\T_{(^\circ F)} = 130\times \displaystyle\frac{9}{5} + 32 = 266^\circ F$

Compound inequality to determine the Fahrenheit temperature range at which the antifreeze protects the car:

$-22 ^\circ F \leq Temperature \leq 266 ^\circ F$