Question

By what length will a slab of concrete that is originally 18 m long contract when the temperature drops from 24°C to -16°C.

Answer 1

Answer:

The length of the slab decreases by 7.2 millimeter if we take the value of coefficient of linear expansion of the slab as $10\times 10^{-6}m/m^{o}C$

Explanation:

Using the formula of linear expansion we have

$\Delta L=L_{o}\alpha \Delta T$

where

$L_{o}$ is the initial length of the slab

$\alpha =10\times 10^{-6}$ is the coefficient of linear expansion of the slab

Applying values we get

$\Delta L=18\times 10\times 10^{-3} \times (-16-24)\\\\\therefore \Delta L=7.2mm$