Answer:
the acceleration is constant
Explanation:
When stone is moving in the air then it has force of gravity on it
Since there is no other force like air friction is to be neglected
so we know that
[tex]F_{net} = mg[/tex]
so we will have
[tex]a = \frac{F_{net}}{m}[/tex]
[tex]a = \frac{mg}{m}[/tex]
[tex]a = g[/tex]
so the acceleration of the stone is always constant and directed vertically downwards with constant magnitude