Respuesta :
Answer:
The correct answer is option 'd': The frequency decreases and the intensity of the sound decreases.
Explanation:
1) Effect on Frequency
According to Doppler's effect of sound we have
for a source of sound moving away from the observer the relation between the observed and the original frequency is given by
[tex]f_{app}=\frac{c-v_{rec}}{c+v_{s}}\times f_{original}[/tex]
where
c = speed of sound in air
[tex]v_{rec}[/tex] is the velocity of observer of sound
[tex]v_{s}[/tex] is the velocity of source of sound
[tex]f_{o}[/tex] is the original frequency of sound
As we see the ratio is less than 1 thus the frequency of sound that the observer receives is less than that of source.
2) Effect on Intensity:
At a distance 'r' from source emitting a wave of Power 'P' is given by
[tex]I=\frac{P}{4\pi r^{2}}[/tex]
As we see on increasing 'r' intensity of sound decreases.
The correct answer is:
(D) The frequency decreases and the intensity of the sound decreases.
Doppler Effect
According to Doppler's effect for a source of sound moving away from the observer the relation between the observed and the original frequency is given by
[tex]\nu_o=\nu[\frac{v-v_o}{v+v_s}][/tex]
where
v = speed of sound in air
v₀ is the velocity of the observer
[tex]v_s[/tex] is the velocity of the source
ν is the original frequency of sound
This shows the frequency of sound for the observer must decrease.
Intensity
The intensity is related with distance as given below:
[tex]I\propto \frac{1}{r^2}[/tex]
It implies that the intensity decreases as distance increases.
Learn more about Doppler Effect:
https://brainly.com/question/1330077?referrer=searchResults