Answer:
The solution set we get is(x,y){(6/4 , 6)}....
Step-by-step explanation:
We have the system of equation:
y = 4x equation 1
8x + y= 18 equation 2
As we see that the first equation has a value of y. Now plug the value of y which is 4x in 2nd equation:
8x+y=18
8x+(4x)=18
12x=18
Divide both sides by 12.
12x/12= 18/12
x= 18/12
x= 6/4
Now plug the value x= 6/4 in equation 1.
y=4x
y=4(6/4)
4 will be cancelled out by 4
y = 6
The solution set we get is(x,y){(6/4 , 6)}....
Answer:
it is not in the options but when i calculate it it was (3/2,6)
Step-by-step explanation:
a.p.e.x (3/2, 6)
