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What amount of carbon dioxide (in moles) is produced from the reaction of 2.24 moles of ethanol with excess oxygen?

Respuesta :

Answer : The amount of carbon dioxide produced is, 197.12 grams.

Explanation : Given,

Moles of ethanol = 2.24 mole

Molar mass of carbon dioxide = 44 g/mole

The balanced chemical reaction will be,

[tex]C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O[/tex]

First we have to calculate the moles carbon dioxide.

From the balanced chemical reaction, we conclude that

As, 1 mole of ethanol react to give 2 moles of carbon dioxide

So, 2.24 mole of ethanol react to give [tex]2\times 2.24=4.48[/tex] moles of carbon dioxide

Now we have to calculate the mass of carbon dioxide.

[tex]\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass of }CO_2[/tex]

[tex]\text{Mass of }CO_2=4.48mole\times 44g/mole=197.12g[/tex]

Therefore, the amount of carbon dioxide produced is 197.12 grams.

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