Respuesta :

Answer:

[tex]\frac{3600\pi}{(\pi +2)^2}[/tex]

Step-by-step explanation:

Given:

Perimeter of the semi-circle = 60 m

let the radius of the semi-circle to be 'r'

Also,

Perimeter of the semi-circle = πr + 2r = ( π + 2 ) × r

on equating, we get

( π + 2 ) × r = 60 m

or

r = [tex]\frac{60}{(\pi +2)}[/tex]

now,

the area of the semi circle = πr² / 2

on substituting the value, we get

area = [tex]\frac{\pi}{2}\times(\frac{60}{(\pi +2)})^2[/tex]

or

area = [tex]\frac{3600\pi}{(\pi +2)^2}[/tex]

Hence,

the area of the semi-circular region =  [tex]\frac{3600\pi}{(\pi +2)^2}[/tex]

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