Answer:
[tex]H (b) = 0.722^b(6)[/tex]
Step-by-step explanation:
The first time the basketball bounces it reaches a height of [tex](1-0.278)(6) = (0.722) (6)[/tex].
The second time the basketball bounces it reaches a height of [tex](0.722) (0.722) (6) = [(0.722) ^ 2] (6)[/tex]. Therefore, after b rebounds the height that the basketball will reach is given by:
[tex]H (b) = 0.722^b(6)[/tex]