Answer:
Step-by-step explanation:
There were 1000 trees in the first year and every year new trees are getting added.
The sequence formed for the new trees every year is
Year 1 2 3
New trees 1000 200 40
We see a geometric sequence has been formed by the new trees added
Ratio of the second year and 1st year trees added = [tex]\frac{200}{1000}=\frac{1}{5}[/tex]
Similarly ratio of trees added in 3rd year to 2nd year = [tex]\frac{40}{200}=\frac{1}{5}[/tex]
So there is a common ratio of [tex]\frac{1}{5}[/tex]
Explicit formula of a geometric sequence representing growth of the trees by
[tex]T_{n}=a(r)^{n-1}[/tex]
where a = number of trees grown first year
r = common ratio
n = number of years
Explicit formula showing the growth of the trees using sigma notation will be
[tex]\sum_{n=1}^{\infty}1000(\frac{1}{5})^{n-1}[/tex]
And Formula for number of trees every year will be
[tex]\sum_{n=1}^{\infty}1000+1000(\frac{1}{5})^{n-1}[/tex]
[tex]\sum_{n=1}^{\infty}1000[1+(\frac{1}{5})^{n-1}][/tex]
Sum of the trees will be
[tex]S=\frac{a}{1-r}[/tex]
= [tex]\frac{2000}{1-\frac{1}{5}}[/tex]
= [tex]\frac{2000}{\frac{4}{5} }[/tex]
= [tex]\frac{2000\times 5}{4}[/tex]
= 2500