Answer:
6/7 revolutions per minute
Step-by-step explanation:
The relative speeds are inversely proportional to the radii, so the larger pulley is rotating at 2/7 the speed of the smaller one.
larger pulley rotation rate = (3 rev/min)(2/7) = 6/7 rev/min
Answer:
The angular speed of the 7 inch pulley is 6/7 or 0.8571 revolutions per minute.
Step-by-step explanation:
Consider the provided information.
Two pulleys, one with radius 2 inches and one with radius 7 inches, are connected by a belt.
It is given that r₁ = 7 in, r₂ = 2 in, ω = 3 rev/min
The angular speed of the 2 inches pulley is 3.
v₁=2×3
v₁=6
Similarly for v₂
Let the angular speed of the 7 inches pulley be ω.
Then its linear speed v₂ is:
v₂=7ω
Equate the linear speed of the pulleys as shown.
v₁=v₂
6=7ω
ω=6/7
ω=0.8571
Hence, the angular speed of the 7 inch pulley is 6/7 or 0.8571 revolutions per minute.
