Question

1.Calculate the end velocity of a rocket that traveled 16km in 2 seconds. distance time 2.Calculate the rockets acceleration m with a start velocity of 0m/s and the end velocity from #1 for 10 seconds. (final velocity- start velocity) time * Be sure to include units!

Answer 1

Answer:

1. 8 km/s 2. 0,8 km/s^2

Explanation:

Velocity:

$v=\frac{16 [km]}{2[s]} =8\frac{km}{s}$

Acceleration:

$a=\frac{8\frac{km}{s}-0\frac{km}{s} }{10[s]}=0,8\frac{km}{s^2}$

Answer 2

Explanation:

1. The rocket covered a distance, $d=16\ km=16000\ m$

Time taken, t = 2 s

The velocity of rocket is given by total distance over total time. It is given by :

$v=\dfrac{d}{t}$

$v=\dfrac{16000\ m}{2\ s}$  

v = 8000 m/s

2. Initial velocity of the rocket, u = 0

Final velocity of the rocket in part 1, v = 8000 m/s

Time taken, t = 10 s

Acceleration of rocket is given change in speed divided by total time. It is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{8000\ m/s}{10\ s}$

$a=800\ m/s^2$

So, the acceleration of the rocket is $800\ m/s^2$. Hence, this is the required solution.