Explanation:
It is given that,
Volume of a neutron, [tex]V=1.4\times 10^{44}\ m^3[/tex]
Mass of the neutron star, [tex]m=1.675\times 10^{24}\ g[/tex]
We need to find the density of the neutron. Density is given by :
[tex]d=\dfrac{m}{V}[/tex]
[tex]d=\dfrac{1.675\times 10^{24}}{1.4\times 10^{44}}[/tex]
[tex]d=1.19\times 10^{-20}\ g/cm^3[/tex]
If the volume of the neutron, [tex]V'=1\ cm^3=10^{-6}\ m^3[/tex]
So, [tex]m'=d\times V'[/tex]
[tex]m'=1.19\times 10^{-20}\times 10^{-6}[/tex]
[tex]m'=1.19\times 10^{-26}\ g[/tex]
[tex]m'=1.19\times 10^{-29}\ kg[/tex]
Hence, this is the required solution.