Answer:
His overall grade is 81.9%
Explanation:
The easiest way to solve this question is by using simple cross multiplication.
1- His overall percentage in exams:
We are given that exams are worth 50% of the grade and that he scored an average of 82.2%
Assume that his overall percentage in exams is e
We can setup the ratio and solve for e as follows:
[tex]\frac{82.2}{100}=\frac{e}{50} \\ \\e=\frac{50*82.2}{100}=41.1[/tex]%
2- His overall grade in quizzes:
We are given that quizzes are worth 30% of the grade and that he scored 74.4%
Assume that his overall percentage in quizzes is q
We can setup the ratio and solve for q as follows:
[tex]\frac{74.4}{100}=\frac{q}{30} \\ \\q=\frac{30*74.4}{100}=22.32[/tex]%
3- His overall grade in homework:
We are given that homework is worth 15% of the grade and that he scored an average of 90%
Assume that his overall percentage in exams is h
We can setup the ratio and solve for h as follows:
[tex]\frac{90}{100}=\frac{h}{15} \\ \\h=\frac{15*90}{100}=13.5[/tex]%
4- His overall grade in class participation:
We are given that class participation is worth 5% of the grade and that he scored a 100% in it
Assume that his overall percentage in exams is p
Since he scored 100%, then he scored the complete worth which is 5%
p = 5%
5- His overall grade in the course:
The student's overall grade in the course is the summation of the above calculated percentages
This means that:
Overall grade = e + q + h + p
Overall grade = 41.1 + 22.32 + 13.5 + 5
Overall grade = 81.92% which is 81.9% approximated to one decimal place
Hope this helps :)
