Question

If the solubility product of silver chromate is 2 x 10-12 at 25°C, what is the solubility in mole/liter of silver chromate?

Answer 1

Answer:

Solubility of silver chromate = $0.7937\times10^{-4}\;mol/L$

Explanation:

Given,

$Ag_2CrO_4\leftrightharpoons2Ag^{+}\;+\;CrO4^{2-}$

Solubility product (Ksp) = 2 x 10-12

at equilibrium, $[Ag^{+}]$ = 2x, $[CrO4^{2-}]$ = x

$Ksp=[Ag^{+}]^{2}[CrO_4^{2-}]\\2\times10^{-12}=(2x)^{2}(x)\\2\times10^{-12}=(4x)^{3}\\(x)^{3} = \frac{2\times10^{-12}}{4}\\\\\sqrt[3]{5\times10^{-13}}$

$x=\sqrt[3]{0.5\times10^{-12}} =0.7937\times10^{-4}\;mol/L$