Answer:
They are not co-linear.
Step-by-step explanation:
For three point's to be co linear the slopes of the lines connecting them should be same
Mathematically we can write for [tex](x_{1},y_{1}),(x_{2},y_{2}),(x_{3},y_{3})[/tex]
to be co-linear we should have
[tex]\frac{y_{3}-y_{2}}{x_{3}-x_{2}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{y_{3}-y_{1}}{x_{3}-x_{1}}[/tex]
Applying the given values we obtain
[tex]\frac{y_{3}-y_{2}}{x_{3}-x_{2}}=\frac{8-6}{0-4}=-1/2\\\\\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{6-2}{4-3}=3\\\\\frac{y_{3}-y_{1}}{x_{3}-x_{1}}=\frac{8-2}{0-3}=-2[/tex]
As we can see the values are not equal thus the points are not co-linear.
