Question

A jet makes a landing traveling due east with a speed of 120 m/s .
If the jet comes to rest in 13.5 s , what is the magnitude of its average acceleration?
What is the direction of its average acceleration? East, West, North or South?

I actually can figure this out if I knew the equation :(

Answer 1

Average acceleration over a time interval lasting $\Delta t$ is

$a_{\rm ave}=\dfrac{\Delta v}{\Delta t}$

where $\Delta v$ is the difference in the jet's final and initial velocities. It's coming to a rest, so

$a_{\rm ave}=\dfrac{0-120\frac{\rm m}{\rm s}}{13.5\,\rm s}=-8.9\dfrac{\rm m}{\mathrm s^2}$

so the average acceleration has magnitude 8.9 m/s^2 and is pointing West (the direction opposite the jet's movement, which should make sense because the jet is slowing down).

Answer 2

The magnitude of a jet's average acceleration is 8.9 m/s^2 and the direction is west.

What is average acceleration?

• The average acceleration is ΔV / ΔT.

• Where , ΔV = difference between final and initial velocity and ΔT = time difference.

What is the average acceleration of a jet ?

• Here a landing speed of the jet is 120 m/s.
• The final speed of the jet is 0 m/s.
• the jet comes to rest in 13.5 s.

So, putting the value in above equation we get,

                  average acceleration =  ΔV / ΔT

                                                        = (0 - 120)/13.5

                                                        = -8.9 m/s^2

Here the minus sign denotes that the direction of the magnitude of average acceleration is opposite of the landing direction of the jet.

Hence, The magnitude of a jet's average acceleration is 8.9 m/s^2 and the direction is west.

Learn more about acceleration here -

https://brainly.com/question/460763

#SPJ2