How many moles of chloride ions are in 0.2550 g of aluminum chloride using AlCl3 's molar mass of 133.34 g / mol:?

Respuesta :

I got 0.001912 using dimensional analysis. See the picture for work.
Ver imagen piggysue

Explanation:

It is known that number of moles is the amount of mass present in a given molar mass of the substance.

Mathematically,   No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

We are given that mass of [tex]AlCl_{3}[/tex] is 0.255 g and molar mass of [tex]AlCl_{3}[/tex] is 133.34 g/mol.

Therefore, number of moles of [tex]AlCl_{3}[/tex] is calculated as follows.

        No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

                              = [tex]\frac{0.255 g}{133.34 g/mol}[/tex]  

                              = [tex]1.912 \times 10^{-3}[/tex] mol

Since, there are three chlorine atoms present in one mole of [tex]AlCl_{3}[/tex]. Therefore, moles of chlorine ions present in given 0.255 g will be calculated as follows.

             [tex]3 \times 1.912 \times 10^{-3}[/tex] mol

            = [tex]5.736 \times 10^{-3} mol[/tex]

Thus, we can conclude that [tex]5.736 \times 10^{-3} mol[/tex] chloride ions are in 0.2550 g of aluminum chloride using [tex]AlCl_{3}[/tex]'s molar mass of 133.34 g/mol.

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