Answer:
0.0737
Step-by-step explanation:
Given that
people surveyed = n = 47
Number of players who said that their favorite position to play is goalkeeper=32
p = Sample proportion of players that their favorite position to play is goalkeeper=[tex]\frac{32}{47} =0.6809[/tex]
q = Player who did not say that their favorite position to play is goalkeeper=1-p = 0.3191
Sample proportion is following normal distribution with mean =[tex]p \\SE =\sqrt{\frac{pq}{n} } \\[/tex]
Std error of sample proportion=[tex]\sqrt{\frac{0.3191(0.6809)}{47} } \\=0.0737[/tex]