Answer:
The new volume becomes twice as large as the initial volume.
Step-by-step explanation:
We know that volume of cylinder is given by
[tex]V=\pi r^{2}h[/tex]
Let the initial radius of the cylinder be 'r' and the initial height of the cylinder be 'h'
Thus the initial volume of the cylinder is given by
[tex]V_{1}=\pi r^{2}h............(i)[/tex]
Since now the height is doubled and the radius remains the same the new volume of the cylinder becomes
[tex]V_{2}=\pi r^{2}\times 2h...........(ii)[/tex]
Comparing i and ii we get
[tex]V_{2}=2V_{1}[/tex]