Question

A bag is filled with 20 pieces of Candy A and 10 pieces of Candy B. If you choose 2 pieces of candy at random without replacement, what is the probability of picking one piece of Candy A first and one piece of Candy B second?

Answer 1

Answer:

0.2298

Step-by-step explanation:

Number of pieces of candy A in the bag = 20

Number of pieces of candy B in bag =10

Total number of pieces =10+20=30

Probability of picking candy A first $=\frac{20}{30}$

Now total number of pieces in the bag =30-1=29 as one piece of candy A is picked out

Now the probability of picking of candy B$=\frac{10}{29}$

So the required probability $=\frac{20}{30}\times \frac{10}{29}=0.2298$