Question

A 6.5-g iron meteor hits the earth at a speed of 295 m/s. If its kinetic energy is entirely converted to heat in the meteor, by how much will its temperature rise?

Answer 1

Answer:

The temperature rise is 92°.

Explanation:

Given that,

Mass of iron = 6.5 g

Speed = 295 m/s

We know that,

specific heat of iron = 113 cal/Kg C°

1 cal = 4.186 J/kg C°

We need to calculate the temperature

Using formula of kinetic energy

$K.E=\dfrac{1}{2}mv^2$...(I)

Formula of heat

$Q=mc\Delta T$....(II)

From equation (I) and (II)

$\dfrac{1}{2}mv^2=mc\Delta T$

$\Delta T=\dfrac{1}{2}\times\dfrac{v^2}{c}$

Put the value into the relation

$\Delta T=\dfrac{295^2}{2\times473.018}$

$\Delta T=91.9=92^{\circ} C$

Hence, The temperature rise is 92°.