Answer:
The correct answer is part 'c' 160 dB
Explanation:
When noise levels of different intensities are superimposed the resultant intensity is given by the equation
[tex]L_{avg}=20log(\frac{1}{N}\sum_{i=1}^{N}(10^{\frac{L_{i}}{20}}))\\[/tex]
where,
[tex]L_{i}[/tex] is the intensity of a general sound level
Since we have 10000 fans each producing sound of 80dB thus the resultant intensity is given using the above formula as
[tex]L_{avg}=20log(\frac{1}{10000}\sum_{i=1}^{10000}(10^{\frac{80}{20}}))\\[/tex]
[tex]\therefore L_{eq}=160dB[/tex]