Answer:
a) The x scalar component of the vector is 460.198 Newtons
b) The y scalar component of the vector is 359.54 Newtons.
Explanation:
The given vector is represented in coordinate axis in the attached figure
We have
[tex]\overrightarrow{F}_{x}=|F|cos(\theta )\widehat{i}\\\\\overrightarrow{F}_{x}=584cos(38^{o})\widehat{i}\\\\\overrightarrow{F}_{x}=460.198\widehat{i}[/tex]
Similarly we have
[tex]\overrightarrow{F}_{y}=|F|sin(\theta )\widehat{-j}\\\\\overrightarrow{F}_{y}=-584sin(38^{o})\widehat{j}\\\\\overrightarrow{F}_{y}=-359.54\widehat{j}[/tex]