Respuesta :

Step-by-step explanation:

in ∆TUW & ∆VWU

∠UTW = ∠UVW (data / given)

WU = WU (common sides) ∠TWU = ∠VUW (TW//UV alternate )

so ∆TUW & ∆VWU are congruent

Answer:

∆TUW≅∆VWU by AAS.

Step-by-step explanation:

Given information: ∠T and ∠V are right angles, TW║UV.

Prove: ∆TUW≅∆VWU

Proof:

If a transversal line intersect two parallel lines, then alternate interior angles are congruent.

In ∆TUW and ∆VWU,

[tex]\angle T\cong \angle V[/tex]                 (Right angles)

[tex]\angle TWU\cong \angle VUW[/tex]                 (Alternate interior angles)

[tex]UW\cong UW[/tex]                     (Reflection property)

By AAS postulate, ∆TUW and ∆VWU are congruent.

[tex]\triangle TUW\cong \triangle VWU[/tex]

Hence proved.

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