Answer:
Step-by-step explanation:
[tex]\frac{2}{3}of total=[/tex] either cow or pigs
[tex]\frac{2}{3}of 60=[/tex]
[tex]\frac{2}{3} X 60=40[/tex]
Either pigs or cow = 40
(1) Let number of pigs be x
then number of cows >twice of pigs = 2x
number of pigs + number of cows = 40
number of cows = 40 -x
40-x > 2x
40 > 3x
x < [tex]\frac{40}{3}[/tex]
x < 12.33
nearest integral number is 12
so its 12
so number of pigs will be 12 so that number of cows = 40 -12 = 28
which is more than twice of number of pigs
28 > 2( 12) = 24
(2) number of pigs + number of cows = 40
for x>12
number of cows = 40 -x
x > 12
-x < -12
adding 40 both sides
40-x < 40-12
number of cows <28