Answer:
9.96 m/s
Explanation:
mass of car, m = 487 kg
radius of track, R = 53.3 m
coefficient of static friction, μ = 0.19
acceleration due to gravity, g = 9.8 m/s^2
let v be the maximum speed so that the car can go without flying off the track.
The formula for the maximum speed is given by
[tex]v_{max}=\sqrt{\mu Rg}[/tex]
[tex]v_{max}=\sqrt{0.19\times53.3\times9.8[/tex]
vmax = 9.96 m/s