Answer:
You need to dissolve 144 gr of glucose in 0.8 liters of water to have a 1 M solution.
Explanation:
Molarity is the amount of moles per liter of solution --> moles/liters. We are trying to get a 1 molar solution and we also know the liters (0,8L) so
[tex]1\frac {moles-of-glucose}{liters-of-water} =\frac{X moles-of-glucose}{0.8 liters-of-water} \\[/tex]
[tex]1\frac{Moles-of-glucose}{liters-of-water } * 0.8 liters of water[/tex]
after canceling liters of water you get 0,8 moles of glucose.
[tex]180 \frac{grams-of-glucose}{mol-of-glucose}*0.8 mol- of- glucose=144 grams-of-glucose[/tex]