Question

If the average (arithmetic mean) of the five numbers x, 7, 2, 16, and 11 is equal to the median of the five numbers, what is the value of x ? (1) 7 < x < 11 (2) x is the median of the five numbers.If the average (arithmetic mean) of the five numbers x, 7, 2, 16, and 11 is equal to the median of the five numbers, what is the value of x ? (1) 7 < x < 11 (2) x is the median of the five numbers.

Answer 1

Answer:

Step-by-step explanation:

Given are five numbers x, 7, 2, 16, and 11

Average = sum/5=$\frac{x+36}{5}$

Median = $\frac{x+36}{5}$

The average of the remaining four numbers = $\frac{36}{4} =9$

If x=9 then average =9 only and also median

will be middle entry of ascending order

2,7,9,11,16

Middle entry = Median = 9

Hence x=9

(1) 7 < x < 11