Answer:
The score corresponds to the 95.82th percentile.
Explanation:
To formula to calculate the percentile in a normal distribution is:
[tex]X=\mu+Z\sigma[/tex]
Where [tex]X[/tex] is the value of the variable, [tex]\mu[/tex] is the mean, [tex]Z[/tex] is the value from the standard normal distribution for the percentile. In this case, you have [tex]X[/tex] and want to know the value of [tex]Z[/tex].
[tex]X=\mu+Z\sigma\\Z\sigma=X-\mu\\Z=\frac{X-\mu}{\sigma} \\Z=\frac{91-65}{15}\\Z=\frac{26}{15}\\Z=1.73[/tex]
The value of [tex]Z=1.73[/tex] in the table of the standard normal distributions gives a value of 0.9582, which means the score is in the 95.82th percentile.