Question

Two samples, each with n = 5 scores, have a pooled variance of 40. What is the estimated standard error for the sample mean difference?​

Answer 1

Answer: 25.30

Step-by-step explanation:

Given : Sample size of both samples : n= 5

A pooled variance : $S_p=40$

The formula to find the standard error for the sample mean difference is given by :-

$S.E.=S_p\sqrt{\dfrac{1}{n_1}+\dfrac{1}{n_2}}\\\\\Rightarrow\ S.E.=(40)\sqrt{\dfrac{1}{5}+\dfrac{1}{5}}\\\\\Rightarrow\ S.E.=(40)\sqrt{\dfrac{2}{5}}=25.2982212813\approx25.30$

Therefore, the estimated standard error for the sample mean difference is 25.30