Answer: 1. [tex]NH_3=82.4\%[/tex]
2. [tex]CO(NH_2)_2=46.7\%[/tex]
3. . [tex]NH_4NO_3=35\%[/tex]
4. [tex](NH_4)_2SO_4=21.2\%[/tex]
[tex]NH_3[/tex] has highest nitrogen content.
Explanation:
To calculate the mass percent of element in a given compound, we use the formula:
[tex]\text{Mass percent of nitrogen}=\frac{\text{Mass of nitrogen}}{\text{Molar mass of nitrogen compound}}\times 100[/tex]
1. [tex]NH_3[/tex]
[tex]\text{Mass percent of nitrogen}=\frac{\text{Mass of nitrogen}}{\text{Mass of} NH_3}=\frac{14}{17}\times 100=82.4\%[/tex]
2. [tex]CO(NH_2)_2[/tex]
[tex]\text{Mass percent of nitrogen}=\frac{\text{Mass of nitrogen}}{\text{Mass of} CO(NH_2)_2}=\frac{14\times 2}{12\times 1+16\times 1+2\times 14+4\times 1}\times 100=\frac{28}{60}\times 100=46.7\%[/tex]
3. [tex]NH_4NO_3[/tex]
[tex]\text{Mass percent of nitrogen}=\frac{\text{Mass of nitrogen}}{\text{Mass of} NH_4NO_3}=\frac{14\times 2}{14\times 2+16\times 3+4\times 1}\times 100=\frac{28}{80}\times 100=35\% [/tex]
4. [tex](NH_4)_2SO_4[/tex]
[tex]\text{Mass percent of nitrogen}=\frac{\text{Mass of nitrogen}}{\text{Mass of}(NH_4)_2SO_4}=\frac{14\times 2}{14\times 2+16\times 4+32\times 1+8\times 1}\times 100=\frac{28}{132}\times 100=21.2\%[/tex]
Thus [tex]NH_3[/tex] has highest nitrogen content of 82.4%.