Question

The water level in a plastic pool changed by -8 gallons each hour due to a small hole in the bottom . after 6 hours the pool contained 132 gallons . how much water was in the pool orginally

Answer 1

The pool is losing 8 gallons per hour.

Multiply the number of gallons per hour by the number of hours:

-8 x 6 = -48

The pool lost 48 gallons in 6 hours.

Now add that amount to the amount in the pool:

48 + 132 = 180 gallons

The pool originally had 180 gallons.