Question

The ages of 3 brothers are represented by consecutive integers. If the oldest brother's age is decreased by twice the younger brother's age, the result is ___________.

Answer 1

Answer:

-x+3 is the result

Step-by-step explanation:

Given that the ages of 3 brothers are represented by consecutive integers.  Let the ages of 3 brothers be x-1, x and x+1 in ascending order.

Oldest brother's age $= x+1$

Twice the younger brother's age =$2(x-1) = 2x-2$

When the above is decreased by twice younger brother age we get

$x+1-(2x-2) = x+1-2x+2\\=-x+3$

Result is -x+3