I have a question that I need answered quickly (it's late and my homework is due soon). I have a few algebra problems that say I need to write each fraction as a sum or difference. For example, 3n+5 over 7. Can someone explain how to solve this?

Respuesta :

Answer:  [tex]\bold{\dfrac{3n}{7}+\dfrac{5}{7}=\dfrac{3n+5}{7}}[/tex]

Step-by-step explanation:

When adding (sum) or subtracting (difference) fractions, the denominator needs to be the same.

There are an infinite number of ways to create the numerator to result in 3n + 5 --> just make sure the denominator for each fraction is 7.

Examples of a sum:

[tex]\dfrac{3n}{7}+\dfrac{5}{7}=\dfrac{3n+5}{7}\\\\\\\dfrac{2n+5}{7}+\dfrac{n}{7}=\dfrac{3n+5}{7}\\\\\\\dfrac{2n+3}{7}+\dfrac{n+2}{7}=\dfrac{3n+5}{7}[/tex]

Examples of a difference:

[tex]\dfrac{4n+5}{7}-\dfrac{n}{7}=\dfrac{3n+5}{7}\\\\\\\dfrac{6n+7}{7}-\dfrac{3n+2}{7}=\dfrac{3n+5}{7}\\\\\\\dfrac{5n+6}{7}-\dfrac{2n+1}{7}=\dfrac{3n+5}{7}[/tex]

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