Question

The first term of an arithmetic sequence is 0 and the common difference is 12. Find the value of the 96th term of the sequence

Answer 1

Answer:

$a_9_6=1,140$

Step-by-step explanation:

we know that

The formula of an arithmetic sequence is

$a_n=a_1+(n-1)d$

where

$a_1$ is the first term

$a_n$ is the nth term

n is the number of terms

d is the common difference

we have

$n=96\\ d=12$

$a_1=0$

substitute the given values

$a_9_6=0+(96-1)(12)$

$a_9_6=1,140$