Write a chemical equation for the reaction that occurs in the following cell: Cu|Cu2+(aq)||Ag+(aq)|Ag. Of the two metals, copper and silver, which is the anode and which is the cathode? Label the oxidizing agent and the reducing agent.

Respuesta :

Answer:

Answer is given below.

Explanation:

Anode is that electrode where oxidation occurs. Cathode is that electrode where reduction occurs.

In cell representation, half cell present left to salt-bridge notation[tex](\parallel )[/tex] is anodic system and another half cell present right to salt-bridge notation[tex](\parallel )[/tex] is cathodic system.

So anode is Cu and cathode is Ag.

oxidation: [tex]Cu-2e^{-}\rightarrow Cu^{2+}(aq.)[/tex]

[reduction: [tex]Ag^{+}+e^{-}\rightarrow Ag[/tex]][tex]\times 2[/tex]

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chemical equation: [tex]Cu+2Ag^{+}(aq.)\rightarrow Cu^{2+}(aq.)+2Ag[/tex]

Oxidizing agent is that species which takes electron from another species. Here [tex]Ag^{+}(aq.)[/tex] takes electron from Cu. Hence [tex]Ag^{+}(aq.)[/tex]  is the oxidizing agent.

Reducing agent is that species which gives electron to another species. Here Cu gives electron to [tex]Ag^{+}(aq.)[/tex] . Hence Cu  is the reducing agent.

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