Answer:
Answer is given below.
Explanation:
Anode is that electrode where oxidation occurs. Cathode is that electrode where reduction occurs.
In cell representation, half cell present left to salt-bridge notation[tex](\parallel )[/tex] is anodic system and another half cell present right to salt-bridge notation[tex](\parallel )[/tex] is cathodic system.
So anode is Cu and cathode is Ag.
oxidation: [tex]Cu-2e^{-}\rightarrow Cu^{2+}(aq.)[/tex]
[reduction: [tex]Ag^{+}+e^{-}\rightarrow Ag[/tex]][tex]\times 2[/tex]
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chemical equation: [tex]Cu+2Ag^{+}(aq.)\rightarrow Cu^{2+}(aq.)+2Ag[/tex]
Oxidizing agent is that species which takes electron from another species. Here [tex]Ag^{+}(aq.)[/tex] takes electron from Cu. Hence [tex]Ag^{+}(aq.)[/tex] is the oxidizing agent.
Reducing agent is that species which gives electron to another species. Here Cu gives electron to [tex]Ag^{+}(aq.)[/tex] . Hence Cu is the reducing agent.