Answer:
The energy in electron volts of a single photon of these X‑rays is 46697.5 eV.
Explanation:
Given that,
Wavelength = 0.0265 nm
We need to calculate the energy
Using formula of energy
[tex]E=\dfrac{hc}{\lambda}[/tex]
Where, h = plank constant
c = speed of light
[tex]\lambda[/tex] = wavelength
Put the value into the formula
[tex]E=\dfrac{6.6\times10^{-34}\times3\times10^{8}}{0.0265\times10^{-9}}[/tex]
[tex]E=7.4716\times10^{-15}\ J[/tex]
We know that,
[tex]1 eV = 1.6\times10^{-19}\ J[/tex]
The energy in eV
[tex]E=\dfrac{7.4716\times10^{-15}}{1.6\times10^{-19}}[/tex]
[tex]E=46697.5\ eV[/tex]
Hence, The energy in electron volts of a single photon of these X‑rays is 46697.5 eV.