Question

kx - 3y = 4
4x - 5y = 7
In the system of equations above, k is a constant
and y are variables. For what value of k will
che sistem of equations have no solution?

Answer 1

Answer:

k=12/5=2.4

Step-by-step explanation:

1. Let's get rid of the variable y

Multiply the first equation by 5 and the second by 3

5kx-15y=20

12x-15y=60

Now subtract from equation(2)/equation(1) -> 12x-5kx=40

x(12-5k)=40 This equation is always solvable except if 12-5k=0, and this happens if k=12/5=2.4

Answer 2

The value of k that will  make the system of equations have no solution is 12/5

Given the system of equations

• kx - 3y = 4 ............ * 5
• 4x - 5y = 7 ............. * 3

Using the elimination method to cancel out the variable y;

5kx - 15y = 20

12x - 15y = 21

Subtract both equations to have:

5kx - 12x = 20 - 21

5kx - 12x =  -1

x(5k-12) = -1

The system of the equation will have no solution is 5k - 12 is equal to zero.

5k - 12 = 0

5k = 12

k = 12/5

Hence the value of k that will  make the system of equations have no solution is 12/5

Learn more on system of equations here: https://brainly.com/question/13729904