Answer:
KOH is a strong base, [tex]HClO_{4}[/tex] is a strong acid, [tex]HNO_{2}[/tex] is a weak acid, NaBr is a soluble salt and [tex]PbCl_{2}[/tex] is an insoluble salt
Explanation:
According to solubility rule, all chlorides, bromides and iodides of metal ions are soluble except for [tex]Pb^{2+},Ag^{+}[/tex] and Hg^{+}[/tex].
Therefore NaBr is a soluble salt and [tex]PbCl_{2}[/tex] is an insoluble salt.
There are seven strong acids : HCl, HBr, HI, [tex]H_{2}SO_{4}[/tex], [tex]HNO_{3}[/tex], [tex]HClO_{3}[/tex] and [tex]HClO_{4}[/tex].
All group IA metal hydroxides e.g. NaOH, KOH etc. are strong base. Also, [tex]Ca(OH)_{2}[/tex], [tex]Sr(OH)_{2}[/tex] and [tex]Ba(OH)_{2}[/tex] are strong bases.
So, KOH is a strong base, [tex]HClO_{4}[/tex] is a strong acid and [tex]HNO_{2}[/tex] is a weak acid.