Answer: [tex]\dfrac{5}{12}[/tex]
Step-by-step explanation:
Given : A coin is tossed and a six-sided die numbered 1 through 6 is rolled.
Then the total number of possible outcomes :-
[tex]2\times6=12[/tex]
The favorable outcomes of tossing a tail and then rolling a number greater than 1 = {(T,2), (T,3), (T, 4), (T,5), (T,6)}
Then , the probability of tossing a tail and then rolling a number greater than 1 is given by :-
[tex]\dfrac{5}{12}[/tex]