Find the point B on Line AC such that the ratio of AB to BC is 3:4
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Answer:
[tex]B(5,1)[/tex]
Step-by-step explanation:
The coordinates of A are (8,-5) and that of C are (1,9).
We want to find the coordinates of B(x,y) that divides [tex]\overline{AC}[/tex].
in the ratio m:n=3:4
This is given by:
[tex]x=\frac{mx_2+nx_1}{m+n}[/tex]
and
[tex]y=\frac{my_2+ny_1}{m+n}[/tex]
We substitute the points and m=3,n=4 to get.
[tex]x=\frac{3*1+4*8}{3+4}[/tex]
[tex]x=\frac{3+32}{7}[/tex]
[tex]x=\frac{35}{7}=5[/tex]
[tex]y=\frac{3*9+4*-5}{3+4}[/tex]
[tex]y=\frac{27-20}{3+4}[/tex]
[tex]y=\frac{7}{7}=1[/tex]
The coordinates are [tex](5,1)[/tex]
Answer:
The point B will be at (5,1)
Step-by-step explanation:
In order to solve this we just have to calculate both components, so in the component x and y, in x the change in units is 7, and in the component y the change is 14.
Since the change is 3:4 AB will be 3x and BC will be 4x
3x+4x=7
7x=7
x=1
3x+4x=14
7x=14
x=2
AB in x measures 3 and in y measures 6.
While BC in x measures 4 and in Y measures 8.
So the point should be at Ax-3 and Ay+6
Ax-3 Ay+6
8-3=5 -5+6=1
The point B will be at (5,1)