Answer: Option (A) is the correct answer.
Explanation:
When weak base [tex]NH_{3}[/tex] is dissolved in water then the reaction will be as follows.
[tex]NH_{3} + H_{2}O \rightarrow NH^{+}_{4} + OH^{-}[/tex]
When [tex]NH_{3}[/tex] is compared with water then oxygen atom of [tex]H_{2}O[/tex] being more electronegative in nature will keep its lone pair of electrons towards itself.
Hence, water will act as a neutral molecule and hence, [tex]NH_{3}[/tex] will act as a stronger base as compared to [tex]H_{2}O[/tex].
On the other hand, [tex]OH^{-}[/tex] will have both lone pair of electrons and a negative charge. Hence, its electron density is much more as compared to [tex]NH_{3}[/tex] that only contains a lone pair of electron.
Therefore, [tex]NH_{3}[/tex] will act as a weak base as compared to [tex]OH^{-}[/tex].
Thus, we can conclude that the statement [tex]OH^{-}[/tex] is a stronger base than [tex]NH_{3}[/tex], is true concerning an aqueous solution of the weak base [tex]NH_{3}[/tex].