Question

Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for opening night totaled $2071.50. The equation 10.50a+3.75b=2071.50 where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how may adult tickets were sold?

Answer 1

Answer: 168 adult tickets were sold.

Step-by-step explanation:

We know that we can find the number of adult and student tickets sold, with this equation:

$10.50a+3.75b=2071.50$

Since 82 students attended, we can substitute $b=82$ into the equation and solve for "a", in order to calculate the amount of adult tickets sold.

Then, "a" is:

$10.50a+3.75(82)=2071.50\\\\10.50a+307.5=2071.50\\\\10.50a=2071.50-307.5\\\\a=\frac{1764}{10.50}\\\\a=168$