Question

Solid cadmium sulfide reacts with an aqueous solution of sulfuric acid . Express your answer as a balanced chemical equation. Identify all of the phases in your answer. nothing

Answer 1

Explanation:

When solid cadmium sulfide reacts with an aqueous solution of sulfuric acid then the reaction will be as follows.

          $CdS(s) + H_{2}SO_{4}(aq) \rightarrow CdSO_{4}(aq) + H_{2}S(g)$

Hence, ionic equation for this reaction is as follows.

      $CdS(s) + 2H^{+}(aq) + SO^{2-}_{4}(aq) \rightarrow Cd^{2+}(aq) + SO^{2-}_{4}(aq) + H_{2}S(g)$

Therefore, net ionic equation for this reaction is as follows.

      $CdS(s) + 2H^{+}(aq) \rightarrow Cd^{2+}(aq) + H_{2}S(g)$

Answer 2

The balanced chemical equation of the reaction between cadmium sulphide and sulfuric acid and it phases is as follows;

CdS(s)+ H₂SO₄(aq) → CdSO₄(aq) + H₂S(g)

Let's represent the chemical equation of each compound.

Cadmium sulphide = CdS

Sulfuric acid  = H₂SO₄

The chemical reaction is represented as follows:

• CdS + H₂SO₄ → CdSO₄ + H₂S

Phase:

The phase is usually use to explain physical and chemical change of this compound. The phases are in liquid, solid, gaseous or aqueous state.

Therefore, the chemical equation with there phases is as follows;

• CdS(s)+ H₂SO₄(aq) → CdSO₄(aq) + H₂S(g)

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