Question

if g(x)=5x-3 and h(x)= sqaure root of x find (g o h)(4)

Answer 1

Answer:

The answer is 7

Step-by-step explanation:

We have:

if g(x)=5x-3 and h(x)= sqaure root of x.

We have to find (g o h)(4).

(g o h) = g(h(x))

Plug the value of h(x) which is √x in g(x)

g(h(x))= g(√x)

Now plug the value √x in g(x).

g(h(x))= g(√x) = 5√x-3

Now to find (g o h)(4) plug in 4 in place of x

(g o h)(x)=g(h(x))= g(√x) = 5√x-3

(g o h)(4)= g(h(4)) = g(√4) = 5√4-3

Therefore:

(g o h)(4) = 5(2)-3

(g o h)(4) = 10-3 = 7

Thus the answer is 7....

Answer 2

Answer:  $(g o h)(4)=7$

Step-by-step explanation:

Given the function g(x):

$g(x)=5x-3$

And the function h(x):

$h(x)=\sqrt{x}$

We need to plug the function  $h(x)=\sqrt{x}$ into the function  $g(x)=5x-3$, in order to find $(g o h)(x)$ . Then:

$(g o h)(x)=5(\sqrt{x})-3$

$(g o h)(x)=5\sqrt{x}-3$

Now, in order to find  $(g o h)(4)$, we need to substitute $x=4$ into $(g o h)(x)=5\sqrt{x}-3$. Then, this is:

$(g o h)(4)=5\sqrt{4}-3$

$(g o h)(4)=10-3$

$(g o h)(4)=7$