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A boy of mass 60 kg and a girl of mass 40 kg are together and at rest on a frozen pond and push each other apart. The girl moves in a negative direction with a speed of 3 m/s. What must be the final velocity of the boy?

Respuesta :

Answer:

2 m/s

Explanation:

Final velocity of the boy will be 2 m/s

What is conservation of momentum?

Conservation of momentum, states that  the quantity called momentum that characterizes motion never changes in an isolated collection of objects; that is, the total momentum of a system remains constant.

m1 = mass of the boy

m2 = mass of the girl

v1 = velocity of boy

v2 = velocity of girl

Using conservation of momentum

momentum of boy + momentum of girl =0

m1 * v1 = -(m2*v2)

60 kg * v1 = - (40 kg * 3 m/s)

v1 = 2m/s

(assuming there is no friction because of frozen pond)

final velocity of the boy will be 2 m/s

learn more about conservation of momentum

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