Question

Two ships leave a harbor at the same time. One ship travels on a bearing S 15 degrees W at 10 miles per hour. The other ship travels on a bearing N 75 degrees E at 11 miles per hour. How far apart will the ships be after 2 ​hours?

Answer 1

Answer:

The distance between the ships after 2 hours will be 36.38 miles.

Explanation:

Given that,

One ship travels on a bearing S 15 degrees W at 10 miles per hour.

The other ship travels on a bearing N 75 degrees E at 11 miles per hour.

After 2 hour,

One ship covered the distance is 20 miles.

Other ship covered the distance is 22 miles.

We need to calculate the distance between the ships

Using cosine rule

$c^2=a^2+b^2-2ab\cos\theta$

Put the value into the formula

$c^2=20^2+22^2-2\times20\times22\cos120$

$c^2=1324$

$c=36.38$

Hence, The distance between the ships after 2 hours will be 36.38 miles.