Given a straight line PQ has a gradient of 3 and passes through a point (4,7)
(1)Find the equation of the straight line PQ
(2)Determine the - x intercept of the straight line PQ

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Answer:

Assign variables to the coordinates of the given points

Let the coordinates of P be (x1;y1) and Q(x2;y2)

x1=−1;y1=−5;x2=5;y2=4

Write down the two-point form of the straight line equation

y−y1x−x1=y2−y1x2−x1

Substitute the values and make y the subject of the equation

y−(−5)x−(−1)y+5x+1y+5y+5y=4−(−5)5−(−1)=96=32(x+1)=32x+32=32x−72

Write the final answer

y=32x−312

Step-by-step explanation:

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