Select the inequality that corresponds to the following graph:

a. 4x+3y≥12
b. 3x+4y<12
c. 3x-4y<12
d. 4x+3y≤12

Select the inequality that corresponds to the following grapha 4x3y12b 3x4ylt12 c 3x4ylt12d 4x3y12 class=

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Answer:

d. 4x+3y≤12

Step-by-step explanation:

To solve the problem we need to find the equation of the red line, since it is part of the inequality.

This should be like the following y=mx+b, where 'm' is the slope.

The slope can be obtained using the following equation:

[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

If we use the points given by the graph (0,4) and (3,0) we will obtain that m=-4/3

Now, to find 'b' we just need to evaluate any point ine equation y=mx+b. iike (0,4).

4=-4/3*0 + b.

b=4

Our line has the following equation: y= -(4/3)*x +4, that can be written in standard form as 3y+4x=12

The region is below the graph, hence our inequality shoul be 3y+4x<=12.

The iqual sign part comes watching the graph, the line is drawn using solid line, hence the line is included in the region.

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